Coloured Ions Questions

  • Questions
  • Answers

The following information is needed for you to be able to answer the question.

  • Planck’s constant is 6.63×10-34
  • The speed of light is 3×108
  1. A Cobalt (II) ion red. State three ways that the colour of the complex can be changed without change the element in the centre of the complex.
  2. Copper (II) sulfate is coloured whereas copper (I) oxide is not.
    1. State the electron configuration of the copper ions in the two compounds.
    2. Explain using the electron configurations why copper (II) ions are coloured whereas copper (I) ions are not.
    3. Copper (II) ions are blue. Explain why this is the case.
    4. Copper ions in a hexaaquacopper (II) complex absorb light of a wavelength of 810nm. Given that the energy of a 3d electron in copper (II) is 2.20×10-19 J, calculate the energy of the excited electron.
    5. Explain why a ligand substitution reaction forming in the formation of [Cu(NH3)4(H2O)]2+ results in a different coloured solution.
  3. Hexaaquairon(II) and hexaaquairon(III) are both coloured complexes.
    1. Explain why they have different colours when dissolved in water.
    2. Nitric acid is added to the iron (III) solution, resulting in a colour change. Explain why this occurs.
    3. The iron (II) complex absorbs light with a wavelength of 365nm. Calculate the energy gap between the ground state d orbital electrons and the excited electrons in kJmol-1The iron (III) complex has an energy gap of 190 kJmol-1 when it absorbs visible light. Use the colour wheel to determine the colour that it should appear.
  4. The following complexes appear to be the following colours. Use the colour wheel to predict the energy gap between the ground state d-orbital electrons and the excited electrons when the complexes absorb light.
    1. [Ni(H2O)6]2+ is green.
    2. [Ni(NH3)4(H2O)2]2+ is blue-green.
    3. [Ni(NH3)6]2+ is blue.
    4. [Cr(OH)6]3- is purple.
  5. The energy gaps for the following complexes are given. State the colour that it will appear.
    1. [Cr(H2O)6]2+ has an energy gap of 185.70 kJmol-1.
    2. [Cr(H2O)6]3+ has an energy gap of 204.75 kJ mol-1.
    3. [CoCl4]2- has an energy gap of 200.30 kJ mol-1.

The following information is needed for you to be able to answer the question.

  • Planck’s constant is 6.63×10-34
  • The speed of light is 3×108
  1. A Cobalt (II) ion red. State three ways that the colour of the complex can be changed without change the element in the centre of the complex.
    Ligand
    Oxidation State
    Co-ordination number
  2. Copper (II) sulfate is coloured whereas copper (I) oxide is not.
    1. State the electron configuration of the copper ions in the two compounds.
      Cu2+: [Ar]3d9
      Cu+: [Ar]3d10
    2. Explain using the electron configurations why copper (II) ions are coloured whereas copper (I) ions are not.
      Copper (II) ions have unfilled orbitals in the d subshell. This means that electrons from a lower energy orbital in the d-subshell can be excited to the unfilled d-subshell orbitals. Copper (I) ions have a full d-subshell and therefore the electrons cannot be excited from a low energy d-subshell orbital to a high energy d-subshell orbital.
    3. Copper (II) ions are blue. Explain why this is the case.
      Copper absorbs red OR red / orange light. All the other frequencies of light are transmitted / reflected. This remaining wavelengths of light produce a blue colour.
    4. Copper ions in a hexaaquacopper (II) complex absorb light of a wavelength of 810nm. Given that the energy of a 3d electron in copper (II) is 2.20×10-19 J, calculate the energy of the excited electron.
      Wavelength of light absorbed in m: 5.98×10-7 m
      Frequency of light absorbed: c / 5.98×10-7 = 5.02×1014 m-1
      Energy of the light absorbed: 5.02×1014 x 6.63×10-34 = 3.326×10-19J
      Excited electron energy: 3.326×10-19 + 2.20×10-19 = 5.53E-19 J
    5. Explain why a ligand substitution reaction forming in the formation of [Cu(NH3)4(H2O)]2+ results in a different coloured solution.
      Different ligands result in d-orbitals that have different amount of energy. This results in different energy gaps and therefore different wavelengths of light are absorbed. This results in a different colour.
  3. Hexaaquairon(II) and hexaaquairon(III) are both coloured complexes.
    1. Explain why they have different colours when dissolved in water.
      Different oxidation number result in d-orbitals that have different amount of energy. This results in different energy gaps and therefore different wavelengths of light are absorbed. This results in a different colour.
    2. Nitric acid is added to the iron (III) solution, resulting in a colour change. Explain why this occurs.
      The Iron (III) solution is very acidic. This means that the water ligands react with water molecules in the following way.
      [Fe(H2O)6]3+ + H2O ⇌ [Fe(H2O)5(OH)]2+ + H3O+
      OR [Fe(H2O)6]3+ ⇌ [Fe(H2O)5(OH)]2+ + H+

      By adding nitric acid, the equilibrium shifts towards the left, change the ligands present.
      Different ligands result in d-orbitals that have different amount of energy. This results in different energy gaps and therefore different wavelengths of light are absorbed. This results in a different colour.
    3. The iron (II) complex absorbs light with a wavelength of 365nm. Calculate the energy gap between the ground state d orbital electrons and the excited electrons in kJmol-1
      Wavelength of light absorbed in m: 3.65×10-7 Frequency of light absorbed: c / 3.65×10-7 = 8.22×1014 m-1
      Energy of the light absorbed: 8.22×1014 x 6.63×10-34 = 5.449×10-19 J
      In kJ mol-1: (5.449×10-19 x 6.022×1023)/1000 = 328 kJmol-1
    4. The iron (III) complex has an energy gap of 190 kJmol-1 when it absorbs visible light. Use the colour wheel to determine the colour that it should appear.
      Energy gap in J: (190 / 6.022×1023)x1000 = 3.155×10-19 J
      Frequency of light: 3.155×10-19 / 6.63×10-34
      Wavelength of light: x / 6.63×10-34 = 6.30×10-7 m
      Wavelength of light in nm: 630 nm.
      Colour: Orange-Red
  4. The following complexes appear to be the following colours. Use the colour wheel to predict the energy gap between the ground state d-orbital electrons and the excited electrons when the complexes absorb light.
    1. [Ni(H2O)6]2+ is green.
      Wavelength of light absorbed in nm: 410
      Wavelength of light absorbed in m: 4.10×10-7
      Frequency of light absorbed: 7.32×1014
      Energy of the light absorbed: 4.851×10-19
      In kJ mol-1: 292 kJ mol-1
    2. [Ni(NH3)4(H2O)2]2+ is blue-green.
      Wavelength of light absorbed in nm: 645
      Wavelength of light absorbed in m: 6.45×10-7
      Frequency of light absorbed: 4.65×1014
      Energy of the light absorbed: 3.084×10-19
      In kJ mol-1: 1856 kJ mol-1
    3. [Ni(NH3)6]2+ is blue.
      Wavelength of light absorbed in nm: 600
      Wavelength of light absorbed in m: 6.00×10-7
      Frequency of light absorbed: 5.00×1014
      Energy of the light absorbed: 3.315×10-19
      In kJ mol-1: 199.63 kJ mol-1
    4. [Cr(OH)6]3- is purple.
      Wavelength of light absorbed in nm: 585
      Wavelength of light absorbed in m: 5.85×10-7
      Frequency of light absorbed: 5.13×1014
      Energy of the light absorbed: 3.400×10-19
      In kJ mol-1: 204.75 kJ mol-1
  5. The energy gaps for the following complexes are given. State the colour that it will appear.
    1. [Cr(H2O)6]2+ has an energy gap of 185.70 kJmol-1.
      Energy gap in J: 3.084×10-19
      Frequency of light: 4.651×1014
      Wavelength of light: 6.45×10-7
      Wavelength of light in nm: 645.01
      Colour: Blue-green
    2. [Cr(H2O)6]3+ has an energy gap of 204.75 kJ mol-1.
      Energy gap in J: 3.400×10-19
      Frequency of light: 5.128×1014
      Wavelength of light: 5.85×10-7
      Wavelength of light in nm: 584.99
      Colour: Purple
    3. [CoCl4]2- has an energy gap of 200.30 kJ mol-1.
      Energy gap in J: 3.326×10-19
      Frequency of light: 5.017×1014
      Wavelength of light: 5.98×10-07
      Wavelength of light in nm: 597.99
      Colour: Blue