Mixed Reactions of Aqueous Ions Questions
- For the following reactions, write the ionic equation for the reaction; state the colour change and state the type of reaction occurring.
- Ammonia solution added to iron(II) sulfate dropwise with a pipette.
- A large quantity of concentrated ammonia added to copper(II) sulfate.
- Copper sulfate and sodium chloride mixed together in a test tube.
- Sodium carbonate solution added to a solution of iron(III) nitrate dropwise.
- Excess concentrated ammonia added to a solution of iron(II) sulfate.
- Hydrochloric acid added to iron(II) hydroxide in a test tube.
- Solid iron(II) hydroxide added to a solution of sodium hydroxide.
- Dilute ammonia added dropwise to iron(III) sulfate.
- Nitric acid added to copper(II) hydroxide in a test tube.
- A large quantity of concentrated ammonia added to a solution of iron(III) sulfate.
- Sodium hydroxide added dropwise to iron(III) hydroxide.
- Limited quantity of sodium hydroxide added to a solution of aluminium nitrate.
- Concentrated hydrochloric acid added to solution of aluminium sulfate.
- Ammonia solution added to aluminium nitrate.
- Dilute ammonia added dropwise to a solution of copper(II) ions.
- Solid sodium carbonate added slowly to a solution of aluminium sulfate.
- Sulfuric acid added dropwise onto aluminium hydroxide.
- Nitric acid added to iron(III) hydroxide
- Sodium carbonate solution added to a solution of iron(II) nitrate.
- For the following colour changes, write the ionic equation for the possible reactions that could have caused that colour change.
- Green solution becomes a yellow solution on the addition of a colourless solution.
- Blue solution forms a blue precipitate on the addition of a colourless solution.
- A green solution becomes a green precipitate on the addition of a colourless solution.
- A blue solution becomes a blue-green precipitate on the addition of a white solid.
- Colourless solution forms a white precipitate on addition of a colourless solution.
- Orange solution forms a brown precipitate on addition of a colourless solution.
- A white precipitate dissolves to form a colourless solution on addition of a colourless solution.
- A lilac solution turns yellow on the addition of a colourless solution.
- Fe(II) sulfate and Fe(III) sulfate undergo different reactions with sodium carbonate solution.
- Write the ionic equation for the two reactions.
- Explain why they undergo different reactions.
- For the following reactions, write the ionic equation for the reaction; state the colour change and state the type of reaction occurring.
- Ammonia solution added to iron(II) sulfate dropwise with a pipette.
[Fe(H2O)6]2+ + 2NH3 –> Fe(H2O)4(OH)2 + 2NH4+
Green solution to green precipitate
Hydrolysis
- A large quantity of concentrated ammonia added to copper(II) sulfate.
[Cu(H2O)6]2+ + 4NH3 –> [Cu(NH3)4(H2O)2]2+ + 4H2O
The blue solution becomes a dark blue solution.
Ligand substitution reaction.
- Copper sulfate and sodium chloride mixed together in a test tube.
[Cu(H2O)6]2+ + 2OH– –> Cu(H2O)4(OH)2 + 2H2O
The blue solution forms a blue precipitate.
Hydrolysis.
- Sodium carbonate solution added to a solution of iron(III) nitrate dropwise.
2[Fe(H2O)6]3+ + 3CO32- –> 2Fe(H2O)3(OH)3 + 3H2O+ 3CO2
Orange solution (or lilac) forms a brown precipitate. Bubbles.
Neutralisation reaction / hydrolysis.
- Excess concentrated ammonia added to a solution of iron(II) sulfate.
[Fe(H2O)6]2+ + 2NH3 –> Fe(H2O)4(OH)2 + 2NH4+
The green solution forms a green precipitate.
Hydrolysis.
- Hydrochloric acid added to iron(II) hydroxide in a test tube.
Fe(H2O)4(OH)2 + 2H+ + 4Cl– –> [FeCl4]2- + 6H2O
Green solid dissolves forming a yellow solution.
Neutralisation reaction followed by a ligand substitution reaction.
- Solid iron(II) hydroxide added to a solution of sodium hydroxide.
No reaction occurs – the solid green precipitate remains solid green.
- Dilute ammonia added dropwise to iron(III) sulfate.
[Fe(H2O)6]3+ + 3NH3 –> Fe(H2O)3(OH)3 + 3NH4+
Lilac (or orange) solution forms a brown precipitate.
Hydrolysis
- Nitric acid added to copper(II) hydroxide in a test tube.
Cu(H2O)4(OH)2 + 2H+ –> [Cu(H2O)6]2+
The blue precipitate dissolves to form a blue solution.
Neutralisation.
- A large quantity of concentrated ammonia added to a solution of iron(III) sulfate.
[Fe(H2O)6]2+ + 2NH3 –> Fe(H2O)4(OH)2 + 2NH4+
The green solution forms a green precipitate
Hydrolysis.
- Sodium hydroxide added dropwise to iron(III) hydroxide.
[Fe(H2O)6]3+ + 3OH– –> Fe(H2O)3(OH)3 + 3H2O
The lilac or orange solution forms a brown precipitate
Hydrolysis.
- Limited quantity of sodium hydroxide added to a solution of aluminium nitrate.
[Al(H2O)6]3+ + 3OH– –> Al(H2O)3(OH)3 + 3H2O
The colourless solution forms a white precipitate
Hydrolysis.
- Concentrated hydrochloric acid added to solution of aluminium sulfate.
[Al(H2O)6]3+ + 4Cl– –> [AlCl4]– + 6H2O
The colourless solution remains a colourless solution.
Ligand Substitution.
- Ammonia solution added to aluminium nitrate.
[Al(H2O)6]3+ + 3NH3 –> Al(H2O)3(OH)3 + 3 NH4+
The colourless solution forms a white precipitate.
Hydrolysis.
- Dilute ammonia added dropwise to a solution of copper(II) ions.
[Cu(H2O)6]2+ + 2NH3 –> Cu(H2O)4(OH)2 + 2NH4+
The blue solution precipitates to form a blue precipitate.
Hydrolysis.
- Solid sodium carbonate added slowly to a solution of aluminium sulfate.
2[Al(H2O)6]3+ + 3CO32- –> 2Al(H2O)3(OH)3+ 3H2O + 3CO2
The colourless solution forms a white precipitate. Bubbles given off.
Neutralisation.
- Sulfuric acid added dropwise onto aluminium hydroxide.
Al(H2O)3(OH)3 + 3H+ –> [Al(H2O)6]3+
The white precipitate dissolves to form a colourless solution.
Neutralisation.
- Nitric acid added to iron(III) hydroxide
Fe(H2O)3(OH)3 + 3H+ –> [Fe(H2O)6]3+
The brown precipitate dissolves forming a lilac or orange solution.
Neutralisation reaction.
- Sodium carbonate solution added to a solution of iron(II) nitrate.
[Fe(H2O)6]2+ + CO32- –> FeCO3 + 6H2O
A green solution forms green precipitate
Precipitation
- For the following colour changes, write the ionic equation for the possible reactions that could have caused that colour change.
- Green solution becomes a yellow solution on the addition of a colourless solution.
Fe(H2O)6 + 4Cl– –> [FeCl4]2- + 6H2O
- Blue solution forms a blue precipitate on the addition of a colourless solution.
[Cu(H2O)6]2+ + 3OH– –> Cu(H2O)3(OH)3 + 3H2O
[Cu(H2O)6]2+ + 3NH3 –> Cu(H2O)3(OH)3 + NH4+
- A green solution becomes a green precipitate on the addition of a colourless solution.
[Fe(H2O)6]2+ + 3OH– –> Fe(H2O)3(OH)3 + 3H2O
[Fe(H2O)6]2+ + 3NH3 –> Fe(H2O)3(OH)3 + NH4+
[Fe(H2O)6]2+ + CO32- –> FeCO3 + 6H2O
- A blue solution becomes a blue-green precipitate on the addition of a white solid.
[Cu(H2O)6]2+ + NaCO3 –> CuCO3 + 6H2O+ Na+
(Note the solid NaCO3 cannot be split up into its ions)
- Colourless solution forms a white precipitate on addition of a colourless solution.
[Al(H2O)6]3+ + 3OH– –> Al(H2O)3(OH)3 + 3H2O
[Al(H2O)6]3+ + 3NH3 –> Al(H2O)3(OH)3 + 3 NH4+
- Orange solution forms a brown precipitate on addition of a colourless solution.
[Fe(H2O)6]3+ + 3OH– –> Fe(H2O)3(OH)3 + 3H2O
[Fe(H2O)6]3+ + NH3 –> Fe(H2O)3(OH)3 + 3NH4+
- A white precipitate dissolves to form a colourless solution on addition of a colourless solution.
Al(H2O)3(OH)3 + OH– –> [Al(H2O)2(OH)4]– + H2O
Al(H2O)3(OH)3 + 3H+ –> [Al(H2O)6]3+
- A lilac solution turns yellow on the addition of a colourless solution.
[Fe(H2O)6]3+ + 4Cl– –> [FeCl4]– + 6H2O
- Fe(II) sulfate and Fe(III) sulfate undergo different reactions with sodium carbonate solution.
- Write the ionic equation for the two reactions.
2[Fe(H2O)6]3+ + 3CO32- –> 2Fe(H2O)3(OH)3 + 3H2O+ 3CO2
[Fe(H2O)6]2+ + CO32- –> FeCO3 + 6H2O
- Explain why they undergo different reactions.
Fe3+ ions are more polarising than Fe2+ ions.
This means that it is easier for the O-H bond in the water ligands to break in the Fe3+ complex that in the Fe2+ complex.
This results in the following reaction: [Fe(H2O)6]3+ + H2O ⇌ [Fe(H2O)5OH]2+ + H3O+
The H3O+ ions react with the carbonate ions.