Variable Oxidation State Questions
- State the oxidation number on the following complexes.
- [Cu(H2O)6]2+
- [Ag(NH3)2]+
- Pt(NH3)2Cl2
- [Fe(H2O)4(OH)2]+
- [Al(OH)4]–
- [Fe(CN)6]3-
- [Co(C2O4)3]4-
- [Cr(H2O)5SO4]+
- Which of the following combinations will react? For those that do react, write the equation for the reaction.
- Lead and Lead (IV) ions.
- MnO2 and Fe2+
- MnO2 and Pb4+
- Co2+ and Cu+
- Cobalt and tetraamminecopper complex
- Hexacyanoferrate (III) and Mn2+
- State the changes you can make to a transition metal ion that can change the ease at which it is oxidised or reduced.
- For the following substances, choose another species that will successfully cause the reaction to occur.
- Co –> Co2+
- Fe3+ –> Fe
- Cr2O72- –> Cr2+
- Mn –> Mn2+
- VO3– –> V3+
- Analyse the following pairs using the electrode potentials data sheet provided.
- Out of MnO4– and H2O2, which is the better oxidising agent?
- Out of Sn4+ and Ag, which is the better oxidising agent?
- Out of Co2+ and Cu, which is the better reducing agent?
- Out of Fe2+ and Sn2+, which is the better reducing agent?
- State the oxidation number on the following complexes.
- [Cu(H2O)6]2+
+2
- [Ag(NH3)2]+
+1
- Pt(NH3)2Cl2
+2
- [Fe(H2O)4(OH)2]+
+3
- [Al(OH)4]–
+3
- [Fe(CN)6]3-
+3
- [Co(C2O4)3]4-
+2
- [Cr(H2O)5SO4]+
+3
- Which of the following combinations will react? For those that do react, write the equation for the reaction.
- Lead and Lead (IV) ions.
Yes
Pb + Pb4+ –> 2Pb2+
- MnO2 and Fe2+
Yes
MnO2 + 4H+ + 2Fe2+ –> Mn2+ + 2H2O + 2Fe3+
- MnO2 and Pb4+
Yes
MnO2 + 2H2O –> MnO4– + 4H+ + 3e–
Pb4+ + 2e– –> Pb2+
2MnO2 + 4H2O + 3Pb4+ –> 2MnO4– + 8H+ + 3Pb2+
- Co2+ and Cu+
No
- Cobalt and tetraamminecopper complex
Yes
[Cu(NH3)4]2+ + 2e– –> Cu + 4NH3
Co –> Co2+ + 2e–
[Cu(NH3)4]2+ + Co –> Cu + 4NH3 + Co2+
OR
[Cu(NH3)4]2+ + Co –> Cu + [Co(NH3)4]2+
- Hexacyanoferrate (III) and Mn2+
No
- State the changes you can make to a transition metal ion that can change the ease at which it is oxidised or reduced.
Oxidation State, ligand, coordination number, pH
- For the following substances, choose another species that will successfully cause the reaction to occur.
- Co –> Co2+
Anything with an Eo higher than -0.28 but lower than 1.82 and is an oxidising agent (must be on the left side of the table), such as Br2.
- Fe3+ –> Fe
Anything with an Eo lower than -0.44 and is a reducing agent (must be on the right side of the table), such as Ca.
- Cr2O72- –> Cr2+
Anything with an Eo -0.41 but higher than -0.91 and is a reducing agent (must be on the right side of the table), such as Zn.
- Mn –> Mn2+
Anything with an Eo higher than -1.18 but lower than 1.23 and is an oxidising agent (must be on the left side of the table), such as Fe3+
- VO3– –> V3+
Anything with an Eo lower than 0.34 but higher than -0.26, and is a reducing agent (must be on the right side of the table), such as Sn2+
- Analyse the following pairs using the electrode potentials data sheet provided here.
- Out of MnO4– and H2O2, which is the better oxidising agent?
MnO4– has an Eo of +1.67 and SO42- has an Eo of +0.17. MnO4– is a better oxidising agent.
- Out of Sn4+ and Ag, which is the better oxidising agent?
Sn4+ has an Eo of +0.15 and Ag has an Eo of +0.8. However, Ag is not an oxidising agent, it is a reducing agent. Sn4+ is the better oxidising agent.
- Out of Co2+ and Cu, which is the better reducing agent?
Co2+ has an Eo of -0.128 but that is it behaving as an oxidising agent. It has an Eo value of +1.82 when it acts as a reducing agent. Cu has an Eo of +0.34. Cu is the better reducing agent.
- Out of Fe2+ and Sn2+, which is the better reducing agent?
Fe2+ has an Eo of -0.44 but that is it behaving as an oxidising agent. It has an Eo value of +0.77 when it is behaving as a reducing agent. Sn2+ has an Eo value of +0.15 when it is behaving as a reducing agent. Fe2+ is the better reducing agent.