Electrophilic Addition Reactions with Asymmetrical Alkenes Questions

Electrophilic Addition with Asymmetry

Alkenes Worksheet
1. But-1-ene and but-2-ene will both undergo electrophilic addition reactions.
a) Explain why the reaction between but-1-ene and hydrogen bromide will produce two organic products.
Answer

The first step of the reaction involves the breaking of the π bond and the formation of a bond between one of the two π-bonded carbons and the hydrogen on HBr. Either carbon can form this bond, so the hydrogen can be added to either carbon-1 or carbon-2.

This leaves either carbon-1 or carbon-2 as the carbocation. When the bromide ion forms a coordinate bond with the carbocation, it can either end up on carbon-1 or carbon-2 depending on where the carbocation was located.

b) Explain why the reaction between but-2-ene and hydrogen bromide will produce only one organic product.
Answer

The two carbons that form the double bond are equivalent (the molecule is symmetrical). No matter which one ends up bonded to the bromine, the resulting product is 2-bromobutane.

c) State which of the two organic products will be the major product and which will be the minor product; explain why that is the case; and outline the mechanism for the minor product.
Answer

Both mechanisms go via a carbocation. The carbocation can end up on either carbon-1 or carbon-2.

  • Carbon-1 would result in a primary carbocation.
  • Carbon-2 would result in a secondary carbocation.

Secondary carbocations are more stable than primary carbocations because there are more alkyl groups attached to the positive carbon. This makes it more stable because the positive inductive effect from the alkyl groups results in a slightly lower positive charge density on the cation.

The more stable carbocation results in the major product, therefore 2-bromobutane is the major product.

2. 1-ethylcyclopentene can react with water in the presence of an acid catalyst.
a) Outline the mechanism for the reaction between 1-ethylcyclopentene and water to make the major product.
Answer Mechanism for 1-ethylcyclopentene hydration
b) Explain why the major product is more frequently made than the minor product.
Answer

In the first step, the π bond is broken and a bond is formed between the hydrogen from the catalyst and one of the two double-bonded carbons. This results in a carbocation.

There are two possible carbocations:

  • The major product involves the formation of a tertiary carbocation.
  • The minor product involves the formation of a secondary carbocation.

The tertiary carbocation is more stable because it has more alkyl groups attached to it (positive inductive effect), dispersing the positive charge more effectively. The more stable intermediate leads to the major product.

3. 3-methylcyclohexene can react with hydrogen chloride.
a) Draw the structure of 3-methylcyclohexene.
Answer Structure of 3-methylcyclohexene
b) State the two possible products and explain which one is the major product.
Answer

The two possible products are:

  • 1-chloro-2-methylcyclohexane (Major Product)
  • 1-chloro-3-methylcyclohexane (Minor Product)

Explanation:

The reaction proceeds via electrophilic addition. The hydrogen ion (H+) adds to the double bond first, creating a carbocation intermediate.

  • Path A: H+ adds to Carbon-1, creating a positive charge on Carbon-2. This is a secondary carbocation attached to the carbon holding the methyl group.
  • Path B: H+ adds to Carbon-2, creating a positive charge on Carbon-1. This is a secondary carbocation attached to a standard -CH2– group.

The carbocation on Carbon-2 is more stable because the adjacent alkyl group (with the methyl substituent) exerts a stronger positive inductive effect than the standard methylene group next to Carbon-1. This extra stability drives the formation of the major product, where the chloride ion attacks Carbon-2.

4. The following molecule has two double bonds. It reacts with hydrogen bromide in the usual way.
Question Molecule
a) State the mechanism for this reaction.
Answer

Electrophilic Addition

b) Draw all the possible structural isomers of the product and order them in terms of their frequency of formation.
Answer Structural Isomers of Product