Nucleophilic Addition of Carbonyls

Nucleophilic Addition of Carbonyls

Carbonyls and Optical Isomerism Worksheet

1. Propanone & Nucleophilic Addition

Propanone can react with a nucleophile to form a hydroxynitrile.
a) What are the reactants and conditions required for the reaction to occur?

Sodium Cyanide (NaCN) followed by a dilute acid (H₂SO₄/HCl).

b) Explain why HCN is not used in this reaction. Give two explanations.

1. Safety: HCN is a toxic gas and is therefore dangerous/difficult to work with.

2. Reaction Rate: HCN is a weak acid and dissociates very poorly (HCN ⇌ H⁺ + CN⁻). This means there is a very low concentration of the nucleophile (CN⁻) available, making the reaction extremely slow.

HCN is not a nucleophile because it does not have a lone pair on the carbon.

c) Outline the mechanism for the reaction.
Mechanism of nucleophilic addition to propanone
d) Explain why propanone is vulnerable to attack by a nucleophile.

The carbonyl carbon is partially positive (δ+) due to the electronegative oxygen atom, making it susceptible to attack by a lone pair of electrons (nucleophile). Additionally, the pi (π) bond between the carbon and oxygen is relatively weak/high energy and breaks easily.

e) Name the product formed.

2-hydroxy-2-methylpropanenitrile

f) Explain why the product has no impact on plane polarised light.

The product molecule does not have a chiral centre. The central carbon is attached to two identical methyl groups (-CH₃), so it is achiral and does not rotate plane polarised light.

2. Propanal & Optical Isomerism

Propanal will also react with the same nucleophile.
a) Outline the mechanism for the reaction.
Mechanism of nucleophilic addition to propanal
b) There are two isomeric products produced in the reaction. Draw the geometry of the two isomers, showing in your answer how they are related to each other.
Enantiomers of 2-hydroxybutanenitrile
c) Explain why the products of the reaction between propanal and the nucleophile has no impact on plane polarised light.

The carbonyl group in propanal is trigonal planar. The nucleophile (CN⁻) can attack the carbonyl carbon from either above or below the plane with equal probability.

This produces a racemic mixture (equal amounts of both enantiomers). As the two enantiomers rotate plane polarised light in opposite directions by the same amount, the effects cancel out.

3. Reduction of Butanone

Butanone can be reduced to form an alcohol.
a) State the reactants and conditions for this reaction.

NaBH₄ (Sodium Borohydride) dissolved in ethanol (or aqueous ethanol).

b) Outline the mechanism for the reduction of butanone.
Mechanism of reduction of butanone
c) Draw the geometry of the two alcohols produced and show how their structures relate to each other.
Enantiomers of Butan-2-ol
d) Explain why a racemic mixture is produced from this reaction.

Butanone is trigonal planar around the carbonyl group. The hydride ion (from BH₄⁻) can attack from above or below the plane with equal probability, producing equal amounts of both enantiomers (a racemic mixture).

4. Distinguishing Tests

Butanone and propanone can be distinguished using tests.
a) Explain why they cannot be distinguished using Tollens’ reagent.

Both molecules are ketones. Ketones cannot be oxidised by mild oxidising agents like Tollens’ reagent, so neither molecule will produce a visible change (no silver mirror for either).

b) Explain why they cannot be distinguished using Potassium dichromate.

As ketones, neither butanone nor propanone can be oxidised by acidified potassium dichromate. Both solutions would remain orange (no reaction).

c) Explain why they cannot be distinguished by reacting them with KCN followed by an acid and then observing their impact on polarised light.
  • Butanone produces 2-hydroxy-2-methylbutanenitrile. This is chiral but forms a racemic mixture, so it is optically inactive.
  • Propanone produces 2-hydroxy-2-methylpropanenitrile. This is achiral (has two methyl groups), so it is optically inactive.

Since neither product rotates plane polarised light, they cannot be distinguished by this method.

d) Suggest a method to tell the butanone and propanone apart.

High Resolution Mass Spectrometry

They have different molecular masses (Propanone Mr = 58.0, Butanone Mr = 72.1). The molecular ion peaks will be at different m/z values.