Boiling Point Trends
Bonding Worksheet
Sketch the boiling points of the halogens and explain the trend.
Answer
- As you go down the group, the atoms have more electrons.
- Larger molecules with more electrons have larger temporary and larger induced dipoles.
- This results in stronger electrostatic attractions between the partially positive and partially negative parts of the molecules (stronger Van Der Waals forces).
Sketch the boiling points of the group 6 hydrides, from H2O to Po2O, and explain the trend.
Answer
- H2O hydrogen bonds whereas the other molecules do not.
- More energy is needed to break the hydrogen bond than is needed to overcome the induced dipole interactions in the other four molecules.
- The increase from H2S to H2Po is due to the atoms getting larger with more electrons as you go down the group.
- This results in stronger induced dipoles, which results in higher boiling points.
Sketch the boiling points of period 3 elements, from Na to Ar, and explain the trend.
Answer
- Na: Metallic bonding.
- Mg: Metallic bonding with stronger force of attraction between the ions in the lattice and the delocalised electrons because the ions are 2+.
- Al: Metallic bonding with stronger force of attraction between the ions in the lattice and the delocalised electrons because the ions are 3+.
- Si: Giant covalent structure with many strong covalent bonds.
- P: Phosphorus is a P4 molecule. It has weak Van Der Waals forces.
- S: Sulfur is S8. Its Van Der Waals forces are stronger because the molecule is larger with more electrons.
- Cl: Chlorine is Cl2. Its Van Der Waals forces are weaker than S8 and P4 because it is a smaller molecule with fewer electrons.
- Ar: Argon is monatomic. It is the smallest with the least electrons, so its Van Der Waals forces are the weakest.