Le Chatelier’s Principle Questions

Le Chatelier’s Principle

Equilibria Worksheet
Define the term Le Chatelier’s Principle.

If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change.

Consider the following reaction, which has an enthalpy change of -98 kJ mol-1:

2SO2(g) + O2(g)
2SO3(g)
a) Using Le Chatelier’s principle, state and explain what would happen to the yield of sulfur trioxide if you were to increase the temperature.

The yield would decrease. This is because the equilibrium would shift in the direction of the endothermic reaction (to the left) to counteract the increase in temperature.

b) State and explain what would happen to the yield of sulfur trioxide if you were to increase the pressure.

The yield would increase. This is because the equilibrium shifts in the direction of the side with the lowest number of gas molecules to counteract the pressure increase. The right side has the least gas molecules (2 moles vs 3 moles), so the equilibrium shifts right.

c) State and explain what would happen to the yield of sulfur trioxide if you were to add a catalyst.

No change. A catalyst increases the rate of the forwards reaction and the rate of the backwards reactions equally.

Consider the following reaction, which is exothermic:

4NH3(g) + 5O2(g)
4NO(g) + 6H2O(g)
a) Using Le Chatelier’s principle, state and explain what would happen to the yield of nitrogen monoxide if you were to increase the temperature.

The yield would decrease. This is because the forward reaction is exothermic. Increasing the temperature causes the equilibrium to shift in the direction of the endothermic reaction (to the left) to absorb the heat.

b) State and explain what would happen to the yield of nitrogen monoxide if you were to increase the pressure.

The yield would decrease. This is because the equilibrium shifts in the direction of the side with the lowest number of gas molecules. The left side has 9 gas molecules and the right side has 10. The equilibrium shifts left to the side with fewer molecules.

Consider the following reaction which has an enthalpy change of -45 kJ mol-1:
C2H4(g) + H2O(g)
C2H5OH(g)
Suggest the conditions of temperature and pressure that would give a good yield and a good rate of reaction.

Temperature: A compromise temperature is used. The reaction is exothermic, so a low temperature favors high yield (equilibrium shifts right). However, too low a temperature results in a slow rate of reaction.

Pressure: A high pressure should be used. There are fewer moles of gas on the right (1 mole) compared to the left (2 moles), so high pressure shifts equilibrium to the right, improving yield. High pressure also increases the rate of reaction by increasing collision frequency.

Note: Pressure is limited by safety and cost considerations in industry.

Consider the following reaction:
HCl(aq) + CH3COONa+(aq)
NaCl + CH3COOH
Explain what happens if you add NaOH to the equilibrium mixture.

If you add NaOH, it reacts with the HCl present (neutralisation). This causes the concentration of HCl to decrease.

The system opposes this change by shifting the position of equilibrium to the left to replace the lost HCl.