Calorimetry Past Paper Questions 2

Q8.

(a)     Amount of hexane = = 0.0233 mol

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q = 4154 x 0.0233 ( = 96.6 – 96.8 kJ)

ecf = M1 x 4154

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Ccal = = 7.79 – 7.81 (kJ K−1)

ecf = M2/12.4

If no other marks awarded, allow one mark for 4154/12.4 = 335

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(b)     q = CcalΔT = 7.79 x 12.2 = 95.0 kJ

Ecf for (a) x 12.2

If candidate converted 12.4 into kelvin in (a), ignore conversion to kelvin in (b)

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(amount of octane == 0.0175 mol)

heat change per mole = = 5417 kJ mol−1

Allow 5420 kJ mol−1

Using the value given:

6.52 x 12.2 = 79.54(4)

79.54/0.0175 = 4545

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(c)     pressure not constant in bomb calorimeter

Allow enthalpy change requires constant pressure

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(d)     100 × 0.2  = 1.64%

12.2

Allow 1.6%

Allow 2% if working shown

NOT 2.0%

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use bigger mass of fuel (so ΔT greater)

Allow octane or hexane as the fuel

Allow more / greater volume of fuel

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